Question

!!!please for the love of God help me!!!

Solve each system by substitution.
{x=y-1
{x+2y=8​

Answer 1

Given :-

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• x=y-1
• x+2y=8

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To find:

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• Value of x
• Value of y

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Solution:-

Let say it is first equation:-

x=y-1. . . . (1)

and this is second equation:-

x+2y=8 . . . . (2)

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Simplifying 1 equation:-

• x = y - 1
• x +1 = y
• y = x + 1

Put this value of y in second equation.

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`\dashrightarrow \sf \: x+2y=8`

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`\dashrightarrow \sf \: x+2(x + 1)=8`

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`\dashrightarrow \sf \: x+2x +2=8`

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`\dashrightarrow \sf \: 3x +2=8`

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`\dashrightarrow \sf \: 3x=8 - 2`

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`\dashrightarrow \sf \: 3x=6`

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`\dashrightarrow \sf \: x=6 / 3`

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`\dashrightarrow \sf \: x= \bf2`

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to find value of y :-

y = x + 1

y = 2 + 1

y = 3

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verification:-

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1 equation:-

x = y - 1

put value of x and y

2 = 3 - 1

2 = 2

LHS = RHS

Hence verified!

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2 equation:-

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• x+2y=8

put value of x and y

• 2 + 2 × 3 = 8
• 2 + 6 = 8
• 8 = 8

LHS = RHS

Hence verified!

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Both equation verified!

.°. value of x and y is 2 and 3 respectively