Answer: 13870
Explanation:
Despite the question has a whole paragraph, it basically asks you when will the function C(x) reach it's minimum point.
I have two ways to solve this problem: Algebra way and Calculus way, and I'll explain both of them.
Algebra way:
There is a formula to determine the x-value of the minimum point of the function: x = (-a)/(2b)
The formula can be used when the function is in the pattern:
y(x) = ax² + bx + c
In this case, a is 1.1, b is -418, and c is 53580.
Therefore, we can find out x-value by (418)/(2 × 1.1) = 190
Now, we just need to substitute x = 190 into the function
and we'll get y = 13870
Calculus way:
I personally like this way because it's faster and easier, but you need to know how to do derivative.
What you need to do is just find out the derivative of the function:
C(x) = 1.1x² - 418x + 53580
C'(x) = 2.2x - 418
Then, we let the derivative C'(x) equal to 0 and find out the x-value:
0 = 2.2x - 418
418 = 2.2x
418/2.2 = x
190 = x
After that, we just need to plug the x into the original function C(x) and find out the y-value