Question 1

Someone help with these two questions. just making sure if what i wrote is correct.

Question 2

$\quad\hookrightarrow\quad \sf {(1)/(2) }$

$\quad\hookrightarrow\quad \sf { (31d-6)/(14)}$

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➲ Question 1 :

$\quad\dashrightarrow\quad \sf { (15p+15)/(10p-20)/ (p+3)/(p-2) }$

$\quad = \quad \sf { (5p+15)/(10p-20)* (p-2)/(p+3)}$

$\quad = \quad \sf {(p(5p+15)-2(5p+15))/(p(10p-20)+3(10p-20)) }$

$\quad = \quad \sf {(5p^2 +15p -10p -30)/(10p^2 -20p+30p-60) }$

$\quad = \quad \sf {(5p^2 +5p -30)/(10p^2 +10p -60) }$

$\quad = \quad \sf { \frac{5\cancel{(p^2+p-6)}}{10\cancel{(p^2+p-6)}}}$

$\quad = \quad \sf {\cancel{(5)/(10)} }$

$\quad = \quad{\pmb{ \sf { (1)/(2)}}}$

➲ Question 2 :

$\quad\dashrightarrow\quad \sf {(5d)/(2)-(2d+3)/(7) }$

$\quad = \quad \sf { (5d* 7 - (2d+3)* 2)/(14)}$

$\quad = \quad \sf { (35d-(4d+6))/(14)}$

$\quad = \quad \sf { (35d-4d-6)/(14)}$

$\quad = \quad{\pmb{ \sf { (31d-6)/(14)}}}$

$\rule{350pt}{2pt}$

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