1 Answer

Dan Pritts · Answer 1 · 2022-11-21T20:33:14+0000

Answer:

$\boxed {\boxed {\sf (4,3) \ is \ not \ a \ solution}}$

Explanation:

If we want to test a solution, we can plug it into the equations and see if it checks out.

We are given the point (4,3). Since points are written (x,y)...

Substitute the values into the first equation.

$11x+9y=17 \\11(4)+9(3)=17$

Multiply.

$44+ 27=17\\$

Add.

$71 \\eq 71$

This does not check out, so we automatically know this point doesn't work. However, we can check the other equation.

$x+y=7 \\4+3=7\\7=7$

Even though the second equation works, BOTH have to work because this is a system of equations. Therefore, (4,3) is not a solution.

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