Question

How many grams of Co3+ are present in 2.34 grams of cobalt(III) nitrite?

Answer 1

`m_(Co^(3+))=0.563gCo^(3+)`

Step-by-step explanation:

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In this case, since these mole-mass relationships are understood in terms of the moles of the atoms forming the considered compound, we first realize that the chemical formula of the cobalt (III) nitrate is Co(NO₃)₃ whereas there is a 1:1 mole ratio of the cobalt (III) ion (molar mass = 58.93 g/mol) to the entire compound. In such a way, we first compute the moles of the salt (molar mass = 58.93 g/mol) and then apply the aforementioned mole ratio to obtain the grams of the required cation:

`m_(Co^(3+))=2.34gCo(NO_3)_3*(1molCo(NO_3)_3)/(244.95 gCo(NO_3)_3) *(1molCo^(3+))/(1molCo(NO_3)_3) *(58.93gCo^(3+))/(1molCo^(3+)) \\\\m_(Co^(3+))=0.563gCo^(3+)`

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