Question

What is the approximate value of f(6)

f(x)= 74/1+2e^-1.5x

PLEASE Round to 2 decimal places

Answer 1

f(6)=0.44626x+74

Explanation:

f(6)=74/1+2(2.718282−1.5)x

f(6)=74/1+2(2.718282−1.5)x

Simplifies to:

f(6)=0.44626x+74

you did not type the question right so I just answer to the best of my understanding. I hope it helps