Question

Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO

Answer 1

`2Mg^0 + O_2^0\rightarrow2Mg^(2+)O^(2-)`

Step-by-step explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

`2Mg^0 + O_2^0\rightarrow2Mg^(2+)O^(2-)`

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