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19 votes
19 votes
the area formula is a parallelogram is equal to (Base)*(height). If the area if a parallelogram is given by the trinomial x^2-14x+24. The base of parallelogram is (x-2), what is an expression for the height of the parallelogram?

User Bolli
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1 Answer

18 votes
18 votes

Answer:

x-12

Step by step Step-by-step explanation:

Here it is given that the area of a parallelogram is given by base * height. And if the area is represented by ,


\longrightarrow A = x^2-14x+24

And the base of the parallelogram is given by,


\longrightarrow Base = x-2

Substituting the values in the given formula, we have;


\longrightarrow Area = base * height


\longrightarrow x^2-14x+24=h(x-2)\\

Divide both sides by (x-2) .


\longrightarrow h =(x^2-14x+24)/(x-2)

Factorise the term in numerator,


\longrightarrow h =(x^2-12x-2x+24)/(x-2)\\


\longrightarrow h =(x(x-12)-2(x-12))/(x-2)\\


\longrightarrow h =((x-2)(x-12))/(x-2)

Simplify,


\longrightarrow \underline{\underline{ height= x-12}}

This is the required answer!

User Omer Van Kloeten
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