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What volume would 7.83 X 10^3 moles of Nitrogen gas occupy?
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What volume would 7.83 X 10^3 moles of Nitrogen gas occupy?

User Tigrish
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1 Answer

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Answer:

29.232 l

Step-by-step explanation:

6.023x10^23 mole of nitrogen =22.4 l

7.83×10^23 mole of nitrogen =

22.4/(6.023×10^23)×7.83×10^23

=29.232 l

User Aclima
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