223k views
2 votes
the area formula is a parallelogram is equal to (Base)*(height). If the area if a parallelogram is given by the trinomial x^2-14x+24. The base of parallelogram is (x-2), what is an expression for the height of the parallelogram?

User Moberg
by
8.2k points

1 Answer

11 votes

Answer:

x-12

Step by step Step-by-step explanation:

Here it is given that the area of a parallelogram is given by base * height. And if the area is represented by ,


\longrightarrow A = x^2-14x+24

And the base of the parallelogram is given by,


\longrightarrow Base = x-2

Substituting the values in the given formula, we have;


\longrightarrow Area = base * height


\longrightarrow x^2-14x+24=h(x-2)\\

Divide both sides by (x-2) .


\longrightarrow h =(x^2-14x+24)/(x-2)

Factorise the term in numerator,


\longrightarrow h =(x^2-12x-2x+24)/(x-2)\\


\longrightarrow h =(x(x-12)-2(x-12))/(x-2)\\


\longrightarrow h =((x-2)(x-12))/(x-2)

Simplify,


\longrightarrow \underline{\underline{ height= x-12}}

This is the required answer!

User Andrew Weir
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories