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What are the zeros of the quadratic function f(x) = 6x^2 + 12x - 7?

User Mcemmy
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1 Answer

3 votes

Answer:

-12 + √(144- 4(-42)/12

-12 + √312/12

-12 + 17.6 / 12

= +.47 and -.47

User Ewindes
by
6.4k points
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