Answer:
![4(19)/(24)](https://img.qammunity.org/2022/formulas/mathematics/high-school/un4di2eidv2jyfgu5k75747khn7kw2hpae.png)
Explanation:
I hope I did this right:
So first thing to do is set up the equation.
![K + (1)/(3) = 5(1)/(8)](https://img.qammunity.org/2022/formulas/mathematics/high-school/mifj4fvc83a5mut1sy5a13jx0rxmeanh67.png)
Next thing to to is subtract 1/3 from both sides to get:
![K = 5(1)/(8) - (1)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/mo1p076kw6psuic6exkjabgo0fym0wiyul.png)
Next up, you will multiply each of the fractions by the opposing value
(multiply 1/8 by 3 and 1/3 by 8)
![K = 5(3)/(24)](https://img.qammunity.org/2022/formulas/mathematics/high-school/rv2dufwn9kbzevw1jzrl88y4iuj2j7pmr1.png)
![-(8)/(24)](https://img.qammunity.org/2022/formulas/mathematics/high-school/bvserdv2frg6dlfynbheezm3znwym6ynsh.png)
Alright almost done, by multiplying 24 by 5 you get 120, that will go in the numerator to make the math a lot easier.
K =
![(123)/(24)](https://img.qammunity.org/2022/formulas/mathematics/high-school/wgcpj3gjzoezbk7zpna32e4xd6sr6wpvlv.png)
![-(8)/(24)](https://img.qammunity.org/2022/formulas/mathematics/high-school/bvserdv2frg6dlfynbheezm3znwym6ynsh.png)
Finally, you subtract 123 over 24 by 8 over 24.
K =
![(123)/(24) - (8)/(24) = (115)/(24)](https://img.qammunity.org/2022/formulas/mathematics/high-school/lep28bkt9hxqr72yu5334620y2wcb287tj.png)
Then just simplfy the 115/24 to get
![4(19)/(24)](https://img.qammunity.org/2022/formulas/mathematics/high-school/un4di2eidv2jyfgu5k75747khn7kw2hpae.png)