Answer:
Approximately 256,140 recent college graduates have accumulated a student loan of more than $30,000.
Explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2022/formulas/mathematics/college/bnaa16b36eg8ubb4w75g6u0qutzsb68wqa.png)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Average cumulative debt of recent college graduates is about $22,500, standard deviation of $7,000.
This means that
![\mu = 22500, \sigma = 7000](https://img.qammunity.org/2022/formulas/mathematics/college/cz4ptanuylq3l6sxfuxhqu77za5rbw8ug1.png)
Proportion more than 30000.
1 subtracted by the pvalue of Z when X = 30000. So
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2022/formulas/mathematics/college/bnaa16b36eg8ubb4w75g6u0qutzsb68wqa.png)
![Z = (30000 - 22500)/(7000)](https://img.qammunity.org/2022/formulas/mathematics/college/ry6e831nn3a7r39pjm8uf5cnue532z3ia0.png)
![Z = 1.07](https://img.qammunity.org/2022/formulas/mathematics/college/y64wpcgskjrmbzm3t8xn1ln3v1eu85tzsn.png)
has a pvalue of 0.8577
1 - 0.8577 = 0.1423
Approximately how many recent college graduates have accumulated a student loan of more than $30,000?
0.1423 out of 1.8 million.
0.1423*1.8 = 0.25614 million = 256,140
Approximately 256,140 recent college graduates have accumulated a student loan of more than $30,000.