44.0k views
3 votes
Graph y ≤ (x + 2)^2.

Click on the graph until the correct graph appears.

Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-1
Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-1
Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-2
Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-3
Graph y ≤ (x + 2)^2. Click on the graph until the correct graph appears.-example-4

2 Answers

2 votes

Answer:

its the first one

Explanation:

our vertex is (-2,0)

so replace it in the equation y ≤ (x + 2)^2

so, 0 ≤ (-2 + 2)^2

= 0 ≤ (-4)^2

= 0 ≤ 16

look at that statement, is 0 less than or equal to 16? Yes. Therefore it is correct, so you shade out side of the parabola.

TIP: If the parabola opens up and:

y <, then shade outside.

y >, then shade inside.

Do the opposite if the parabola opens down.

7 votes

Answer:

the first one is the correct one

Explanation:

a great way to check this is to use demos .com

User Shaurya Mittal
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.