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Unit 7 polynomials and factoring homework 7 factoring trinomials answer key

User Shushant
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1. x² + 5x + 6 factors are (x + 2)(x + 3)

2. m² + 18m + 56 factors are (m + 14)(m + 4)

3. y² + 9y + 8 factors are (y +8)(y + 1)

4. y² - 6y +8 factors are (y - 4)(y - 2)

5. n² - n + 90 factors are (n -
(1- √(-359) )/(2) )(n +
(1- √(-359) )/(2))

6.
x^2 + 3x - 70 factors are (x + 10)(y - 7)

7. m² + 5m - 6 factors are (m + 6)(y - 1)

8.
x^2 - 10x - 39 factors are (x + 13)(y - 3)

9.
x^2 - 14x - 51 factors are (x - 17)(y +6)

To get the factors we will use the formula


(-b +- √(b^2-4ac) )/(2a)

a , b and c value we find by comparing the given equation with
ax^2 +bx + c

Here's the answer key for Unit 7 Polynomials and Factoring Homework 7 Factoring Trinomials:

1. x² + 5x + 6

x =
(-5 +- √(5^2-4(1)(6)) )/(2(1))

x =
(-5 +- √(25-24) )/(2)

x =
(-5 +- √(1) )/(2)

x =
(-5 +- 1 )/(2)

x = -3, -2

Factors: (x + 2)(x + 3)

2. m² + 18m + 56

m =
(-18 +- √(18^2-4(56)) )/(2(1))

m =
(-18 +- 10)/(2)

m = -14, -4

Factors: (m + 14)(m + 4)

3. y² + 9y + 8

y =
(-9+- √(9^2-4(8)) )/(2(1))

y =
(-9+- 7)/(2)

y = - 8, -1

Factors: (y +8)(y + 1)

4. y² - 6y +8

y =
(6+- √(6^2-4(8)) )/(2(1))

y =
(6+- 2 )/(2)

y = 4, 2

Factors: (y - 4)(y - 2)

5. n² - n +90

n =
(1+- √(1^2-4(90)) )/(2(1))

n =
(1+- √(-359) )/(2)

n =
(1- √(-359) )/(2) ,
(1+ √(-359) )/(2)

Factors: (n -
(1- √(-359) )/(2) )(n +
(1- √(-359) )/(2))

6.
x^2 + 3x - 70

x =
(-3+- √(3^2-4(70)) )/(2(1))

x =
(-3+- √(3^2-280) )/(2)

x =
(-3+-17)/(2)

x = -10, 7

Factors: (x + 10)(y - 7)

7. m² + 5m - 6

m =
(-5+- √(5^2-4(-6)) )/(2(1))

m =
(-5+- 7 )/(2)

m = -6, 1

Factors: (m + 6)(y - 1)

8.
x^2 - 10x - 39

x =
(10+- √(10^2-4(-39)) )/(2(1))

x =
(10+- 16 )/(2)

x= - 13, 3

Factors: (x + 13)(y - 3)

9.
x^2 - 14x - 51

x =
(14+- √(14^2-4(-51)) )/(2(1))

x =
(14+- 20)/(2)

x = 17, -6

Factors: (x - 17)(y +6)

Question:-

1.
x^2 + 5x + 6

2. m² + 18m + 56

3. y² + 9y + 8

4. y² - 6y +8

5. n² - n +90

6.
x^2 + 3x - 70

7. m²+5m-6

8.
x^2 - 10x - 39

9.
x^2 - 14x - 51

User Argas
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