Question

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A company set aside a certain amount of money in the year 2000. The company spent exactly the same amount from that fund each year on perks for its employees. In 2003 , there was still $790,000left in the fund. In 2005, there was $702,000 left.
Let x be the number of years since 2000, and let y be the amount of money, in dollars, left in the fund that year. Use a linear equation to model the amount of money left in the fund after so many years.

The linear model’s slope-intercept equation is _____

In the year 2009, there was _____ left in the fund.

In the year _____, the fund will be empty.

Answer 1

Linear Equation: y=-44000x+88922000

Year 2009: $526000

By year 2021, they have no more fund

Explanation:

Slope formula is difference of y/difference of x. 79000-70200/2003-2005=

-88000/2=-44000.

To find the y intercept, x=0.

It should be year 0. 44000x2003=88132000+790000=88922000

Now put it into y=mx+b

y=-44000x+88922000

Plug in 2009.

It should equal 526000.