Question

Please help, I understand how to do the first half of the problem, but don’t know how to solve for the second equation!!

Answer 1

an absolute value equation is always a twin equation in disguise, so

`6|x-7|=48\implies |x-7|=\cfrac{48}{6}\implies |x-7|=8\implies \pm(x-7)=8 \\\\[-0.35em] ~\dotfill\\\\ +(x-7)=8\implies \boxed{x=15} \\\\[-0.35em] ~\dotfill\\\\ -(x-7)=8\implies x-7=-8\implies \boxed{x=-1}`