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Find the value of x. Round to the nearest tenth (one decimal place)
19
21

Find the value of x. Round to the nearest tenth (one decimal place) 19 21-example-1
User Cstrutton
by
4.7k points

2 Answers

1 vote

Answer:

x = ~8.9

Explanation:

a^2 + b^2 = c^2

c is the long side

a and b are the other two shorter sides

this means

x^2 + 19^2 = 21^2

x^2 + 361 = 441

x^2 = 441- 361

x^2 = 441- 361

x^2 = 80

square root of 80 = ~8.9

x = ~8.9

User TahitianGabriel
by
4.6k points
5 votes

Using the Pythagorean theorem:

X = sqrt(21^2 - 19^2)

X = sqrt(441 - 361)

X = sqrt(80)

X = 8.944

Rounded to the nearest tenth = 8.9

User Crowstar
by
4.6k points