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CaC2 + 2H2O ⟶ C2H2 + Ca(OH)2 If 32.0g CaC2 are used in this reaction, how many moles of calcium hydroxide are produced?
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CaC2 + 2H2O ⟶ C2H2 + Ca(OH)2

If 32.0g CaC2 are used in this reaction, how many moles of calcium hydroxide are produced?

User SKFox
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0.499 mol

Explanation: M(CaC2) = 64.1 g/mol, n= m/M = 32.0 g/ 64.1 g/ mol= 0.499 mol

Amount of Calcium hydroxide Is same

User Jeffrey Hulten
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