Question

A 50kg crate is being push on a horizontal floor at constant velocity. Given that the coefficient of kenitic friction between crate and floor is hk=0.1 . What is the push force?​

Answer 1

F = 49 N

Step-by-step explanation:

For this exercise we must use Newton's second law. Let's set a reference frame with the x axis parallel to the floor.

As they indicate that the box is going at constant speed, its acceleration is zero

Y axis y

N-W = 0

N = mg

X axis

F-fr = 0

F = fr

the friction force has the formula

fr = μ N

fr = μ mg

we substitute

F = μ m g

let's calculate

F = 0.1 50 9.8

F = 49 N