Answer:
1)
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2)
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Explanation:
1)
We need to use the property of power and logarithms, particularly this:
(1)
So, let's take take the exponent:


now, we can write the negavitve power as:

So, the aswer will be:
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2)
Applying equation 1, let's take log in base 2 on each side of the equation

using the power definition in log, we have:

Therefore, the answer is:
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I hope it helps you!