Question

Please help it’s the last question

Answer 1

`y=`
`-(5)/(6)x - 1` is the answer

Explanation:

Equation of the line: y = 6/5x + 1

= 5y = 6x + 5

= 6x - 5y + 5

Equation of the perpendicular line: bx - ay + k = 0

= -5x -6y + k = 0

Equation passes through (6,-6),

-5(6) -6(-6) + k = 0

-30 + 36 + k = 0

6 + k = 0

k = -6

Substituting,

-5x -6y + k = 0

-5x -6y -6 = 0

-6y = 5x + 6

`y=`
`-(5)/(6)x - 1` (Slope-Intercept form)