Question

What is the molality of a solution containing 18.2 g HCl and 250. g of water?
(EZ Points here)

Answer 1

1.99M

Step-by-step explanation:

Molality can be calculated by dividing the moles of solute by the mass of the solvent i.e.

Molality (M) = n of solute (mol) ÷ mass of solvent (kg)

Based on the information, mass of HCl (solute) = 18.2g, mass of solvent (water) = 250.0g

mole of solute = mass/molar mass

Molar mass of HCl = 1 + 35.5 = 36.5g/lol

mole = 18.2/36.5

mole = 0.499mol

Mass of solvent = 250.0g

In Kg, mass of water = 250/1000

= 0.250Kg

Molality = 0.499/0.250

Molality = 1.996

Molality of the solution = 1.99M