Question

The pressure in a tire is 101 kPa at 10.0°C, what will be the pressure of a tire at 45.0°C?

Answer 1

P₂ = 113.49 kPa

Step-by-step explanation:

Given that,

Initial pressure, P₁ = 101 kPa

Initial temperature, T₁ = 10.0°C = 283 K

Final temperature, T₂ = 45°C = 318 K

The relation between pressure and temperature is given by :

`(P_1)/(T_1)=(P_2)/(T_2)`

Where

P₂ is the new pressure

So,

`P_2=(P_1T_2)/(T_1)\\\\P_2=(101 * 318)/(283 )\\\\P_2=113.49\ kPa`

So, the new pressure is equal to 113.49 kPa.