Question

Identify the center and radius of the circle with the following equation:
`\displaystyle(x+3)^2+(y+(3)/(2))^2=4`

Answer 1

Explanation:

Hey there!

Given;

The equation of a circle is:(X+3)² + (y+3/2)² = 4.

Comparing the equation with (x-h)²+(y-k)² = r², we get;

Centre (h,k) = (-3,-3/2)

Radius (r) = 2 units.

Hope it helps!

Answer 2

Hey there,

The equation is already written in circle equation form but if needed, here is what it will look like when it isn't simplified.

(x - (-3))² + (y - (-3/2))² = 2²

With this, the circle has a center at (-3, -3/2) and a radius of 2.

Best of Luck!