148k views
5 votes
What is the vertex for the following quadratic?
f(x)= 2x^2-12x+16

What is the vertex for the following quadratic? f(x)= 2x^2-12x+16-example-1
User Brkr
by
7.7k points

1 Answer

5 votes

Answer:

(3, -2)

Explanation:

To find the vertex, put the equation into vertex form by completing the square

2(x^2 - 6x) + 16 [pulling out the 2]

2(x^2 - 6x + 9) - 18 + 16 [completing the square, you subtracted 2*9 = 18 so you also add 18]

2(x - 3)^2 - 2 [simplify the equation]

vertex is (3, -2)

User Liszt
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories