Question

In triangle nop the measure p=90degrees n=27 degrees and pn= 50 feet find the length of no to the nearest tenth

Answer 1

56.1feet

Explanation:

Triangle NOP is a right angled triangle;

NP is the adjacent side = 50feet

NO is the hypotenuse

m<N = 27degrees

Using the SOH CAH TOA identity;

Cos theta = Adjacent/Hypotenuse

Cos m<N = NP/NO

Cos 27 = 50/NO

NO = 50/cos27

NO = 50/0.8910

NO = 56.1 feet

Hence the length of NO to the nearest tenth is 56.1feet