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(11a2b+17a-4b2+15)+(12a2b-16b2+3)=

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(11a2b+17a-4b2+15)+(12a2b-16b2+3)=

asked May 17, 2022 227k views

1 vote

(11a2b+17a-4b2+15)+(12a2b-16b2+3)=

Mathematics
college

Narek Malkhasyan asked

by Narek Malkhasyan

8.3k points

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2 Answers

4 votes

This is kinda confusing

Paul Dixon answered May 17, 2022

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1 vote

Answer:

232−202+17+18

Carolin answered May 23, 2022

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