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A sample of hydrogen changes its pressure from 756 torr to 499 torr while the temperature remains constant. After the pressure is reduced, the volume of the gas is 789 mL. What was the original volume?​

1 Answer

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P1 = 756 torr

P2 = 499 torr

V2 = 789 mL

V1 = ?

applying Boyle's Law

P1 * V1 = P2 * V2

756 torr * V1 = 499 torr * 789 mL

V1 = 499 torr * 789 mL / 756 torr

V1 = 520.78 mL

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