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A system has an infinite number of solutions. one equation is 3x-3y=8. Which could be the other equation in the system of equations?

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Answer:


6x-6y-16=0

Explanation:

Consider the following system of equations:


a_1x+b_1y+c_1=0\\\\a_2x+b_2y+c_2=0

The system of equations has infinite solutions if
(a_1)/(a_2)=(b_1)/(b_2)=(c_1)/(c_2)

One equation is
3x-3y=8


3x-3y-8=0

Take another equation as
6x-6y-16=0

So, the two equations are
3x-3y-8=0 and
6x-6y-16=0


a_1=3,b_1=-3,c_1=-8,a_2=6,b_2=-6,c_2=-16


(a_1)/(a_2)=(3)/(6)=(1)/(2)\\ (b_1)/(b_2)=(-3)/(-6)=(1)/(2)\\ (c_1)/(c_2)=(-8)/(-16)=(1)/(2)

So,


(a_1)/(a_2)=(b_1)/(b_2)=(c_1)/(c_2)

Therefore, another equation can be
6x-6y-16=0

User DrWhat
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