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A line passes through the point (-8, 1) and has a slope of 5/4

User Epichorns
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1 Answer

4 votes

Answer:

The equation is: y y = 5/4 * x - 13

Explanation:

The slope-intercept y = mx + c form of a straight line is In this case we have a point, (x, y) and the slope, m so all we need is a value for c. Substitute into y = mx + c - 3 = 5/4 * (8) + c - 3 = 10 + c c = - 13 y = 5/4 * x - 13 The equation is: y Or you can use the formula for the situation where you have a point, (x 1 ,y 1 ) and the slope, (m) y-y 1 =m(x-x 1 ) y - (- 3) = 5/4 * (x - 8) y + 3 = 5/4 * x - 10 y = 5/4 * x - 13

User Dan Stoppelman
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