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What is the equation of the line that passes through the point (1,-3) and has a slope of -3? PLEASE HURRY

User LachoTomov
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(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -3 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-3}(x-\stackrel{x_1}{1}) \\\\\\ y+3=-3x+3\implies y=-3x

User Lord Midi
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