Question

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How much energy is released when 944.3 g of phosphoric acid is produced
P4O10(g) + 6H20(l) -- > 4H3PO4(aq)+424 kj

Answer 1

1024.84 Kj

Step-by-step explanation:

P₄o₁₀(g) + 6H₂O(l) => 4H₃PO₄(aq) + 424Kj

moles H₃PO₄ = (944.3g H₃PO₄) /(97.994g H₃PO₄ /mole H₃PO₄)

= 9.64 moles H₃PO₄

From equation reaction ratios ...

4 moles H₃PO₄ => 424 Kj

9.64 moles H₃PO₄ => (?)

4 moles H₃PO₄/9.64 moles H₃PO₄ = (424Kj)/(?)

Energy Released (Kj) = (424Kj)(9.64moles)/(4moles) = 1021.84 Kj