Answer:
The correct solution is "21024 KWh/degree day".
Step-by-step explanation:
The given query is incomplete. Below is the attachment of complete query is provided.
The given values are:
Indoor design temperature:
= 70°F
Now,
According to the question,
The heat loss annually will be:
=
![12* 24* 365](https://img.qammunity.org/2022/formulas/engineering/college/d4n8mosrm4kfsznvmbu8xomattcdynm82x.png)
=
![105120 \ KW](https://img.qammunity.org/2022/formulas/engineering/college/tmdychdt1jflvemvovk3pzdzq5fsiflgfk.png)
Degree days will be:
=
![75-65](https://img.qammunity.org/2022/formulas/engineering/college/n761u3lgxsr6wjvhs5r283br1446mnjxfo.png)
=
![5](https://img.qammunity.org/2022/formulas/mathematics/high-school/ygbi3prz9qvtsl371t8ku8dxuz50kw8f8u.png)
Hence,
Annual KWh use will be:
=
![(Heat \ loss \ annually)/(degree \ days)](https://img.qammunity.org/2022/formulas/engineering/college/93w8m33ytlps6mp6zp9yto2zjgynmfg4qu.png)
On substituting the values, we get
=
![(105120)/(5)](https://img.qammunity.org/2022/formulas/engineering/college/p5ymthq6w445bnrafeb8a7lp5yjw9jsas1.png)
=
![21024 \ KWh/degree \ day](https://img.qammunity.org/2022/formulas/engineering/college/gux9h5lld9cbitgkicy2gtgkw2v2ylbpsz.png)