Question

What is the equation of a circle with a center at (−3, 2) and radius 16?

Answer 1

(x+3)^2 + (y+2)^2 = 16

Explanation:

hi!

so the equation of a circle with the center (h,k) and a radius r is:

(x-h)^2+(y+k)^2 = r^2

- h is the x value

- k is the y value

- r is the radius

so using your information you can plug in the given values into the "blanket" formula

which would result in:

(x--3)^2 + (y+2)^2 = 16^2 --> since there is a double negative, you can change that to a positive :)

this means that your equation is:

`(x+3)^(2) + (y+2)^(2) = 16^2`

and you can even simplify 16^2 = 256

end formula!

`(x+3)^(2) +(y+2)^(2) = 256`