Question

A ball is thrown into the air with an initial upward velocity of 48 feet/second. If height h in

feet after t seconds is given by the function h(t) = – 16t2 + 48t + 4.
a) What height will the ball be when 2 seconds has passed?

b) In how many seconds will the ball reach its maximum height?

c) What is the ball’s maximum height?
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Answer 1

Explanation:

after 2 seconds the ball would be 96 feet in the air

in 9 seconds will it reach its max height

max height=136ft