Question

The area of the rectangle is 72a^3b^4. What is the length of the rectangle?

Answer 1

Area of a rectangle is equal to W*L (given)

Width is 6ab (given)

L = area/width

`(72a^(3)b^(4))/(6ab) = L\\`

Solve for 72/6... 12

`a = a^(1)`

`(12a^(3)b^(4))/(a^(1)b^(1)) = L\\`

When dividing exponents, substract the smaller one which is on the bottom from the bigger one on top

`12a^(2)b^(3) = L`