Question

How many grams of aluminum foil will be produced, when you decompose 444.71 g of aluminum oxide (Al


`al2o3|`
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Answer 1

889.4 g of Al are produced in the decomposition of 444.71 g of Al₂O₃

Step-by-step explanation:

This is the reaction of decomposition:

2Al₂O₃ → 4Al + 3O₂

2 moles of aluminum oxide decompose to 4 moles of Al and 3 moles and oxygen.

We convert the mass to moles:

444.71 g . 1mol /26.98g = 16.48 moles.

Now, we can apply the rule of three:

2 moles of Al₂O₃ decompose to 4 moles of Al

Then, 16.48 moles of Al₂O₃ may decompose to (16.48 . 4) /2 = 32.9 moles.

We convert the moles to mass:

32.9 mol . 26.98 g/ mol = 889.4 g