Question

A gas has a volume of 590 mL at a temperature of –55.0°C. What The temperature be if the volume expands to 15L at constant pressure?

Answer 1

5542.37 K

Step-by-step explanation:

Given that,

Initial volume, V₁ = 590 mL

Initial temperature, T₁ = -55°C = -55 + 273 = 218 K

Final volume, V₂ = 15 L

We need to find the final temperature of the gas. The relation between the volume and the temperature is given by :

`(V_1)/(T_1)=(V_2)/(T_2)`

Where

T₂ is final volume of the gas

Put all the values in above relation,

`T_2=(V_2T_1)/(V_1)\\\\T_2=(15\ L* 218\ K)/(590* 10^(-3)\ L)\\\\T_2=5542.37\ K`

So, the required temperature is equal to 5542.37 K.