Question

The length of a rectangle is 20 inches less than twice the width. The perimeter of the rectangle is 86 inches. Find the dimensions of the rectangle.

Answer 1

length=22

width=21

Explanation:

let, length be x and width be y.

x=2y-20

2(x+y)=86

or, 2(2y-20+y)=86

or, 2(3y-20)=86

or, 6y-40=86

or, 6y= 126

or, y= 126/6

y= 21

x= 2×21-20 = 42-20 =22