Question

Which gives an equation for the line perpendicular to y = 2/3x + 1 that contains (0, 2) * O y = 3/2x + 2 O y = -3/2x + 2 O y = 3/2x-2 O y = -3/2x-2​

Answer 1

`y = -(3)/(2)x + 2`

Explanation:

Equation of a line:

The equation of a line has the following format:

`y = mx + b`

In which m is the slope and b is the y-intercept(value of y when x = 0).

If two lines are perpendicular, the multiplication of their slopes is -1.

Contains (0, 2)

This means that
`b = 2`. So

`y = mx + 2`

Finding the slope:

Perpendicular to y = 2/3x + 1 means that:

`(2m)/(3) = -1`

`2m = -3`

`m = -(3)/(2)`

So

`y = -(3)/(2)x + 2`