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Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm. How much greater was the volume of air in the larger ball than the smaller ball? Use 3. 14 to approximate pi. Round to the nearest hundredth if necessary. Enter your answer as a decimal in the box. Cm³.

User Cryss
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1 Answer

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Answer:

Difference of volume of air =
17182.08cm^(3)

Explanation:

Radius of ball = 18 cm

Volume of big ball =
(3)/(4) \pi o^(3)

= 4/3 x * 14 X 18
^(3)

= 7324g * g2/ 3

= 24416.64cm^3

Radious of another (small ball) = 12 cm

Volume of small ball =
(3)/(4) \pi R^(3)

= 4/3 x 3 * 14 X 12^3

= 21703.68/ 3

= 7234 * 56cm^3

Difference of volume =
v_(b) -v _(s)

= 24416 * 64 - 7234 * 56cm^3

= 17182 * 08 cm^3

User Scomes
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