Question

A toy car with a mass of 8 kg and velocity of 5 m/s to the right collides with a 5.28 kg car moving to the left with a velocity of 1.65 m/s. After the collision, the 8 kg car continues forward with a velocity of 0.5 m/s. What is the new velocity of the 5.28 kg car after the collision?

Answer 1

This is a case of elastic collision.
The equation is m1v1i+m2v2i=m1v1f+m2v2f
Substituting we get:
(8)(5)+(5.28)(-1.65)=(8)(0.5)+(5.28)(v2f)
V2f=5.168m/s