Answer:
his distance is too small (r = 0.01 mm), therefore the cut can be at any distance
Step-by-step explanation:
For this exercise let's use the ampere law.
Let's use a cylinder as the circulating surface
∫ B. ds = μ₀ I
in this case the field is circular and ds is circular therefore the angle between them is zero and cos 0 = 1
B 2π r = μ₀ I
r =
The field needed to demagnetize the card is B = 1000 gauss = 0.1 T
r =
r = 2 10⁻⁷ 5.0/0.1
r = 1 10⁻⁵ m
this distance is too small (r = 0.01 mm), therefore the cut can be at any distance