Question

Given that f(x) = x2 + 1 and g(x) = -3, multiply the functions (gºf)(x).

A) (gºf)(x) = -3x2 - 3
B)(gºf)(x) = -3x2 + 3
C)(gºf)(x) = 3x2 + 3
D)(g. f)(x) = 3x2 - 3

Answer 1

`(g\cdot f) = -3x^2-3`

Explanation:

`f(x) = x^2 + 1`

`g(x) = -3`

The problem state to multiply the function
`f` and
`g` so the symbol seems to be incorrect.

We actually want to calculate

`g(x) f(x) =gf(x) = (-3) \cdot (x^2+1)= -3x^2-3`

Note

`g\circ f(x)=g(f(x))=g(x^2+1)=-3`