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the length width and height of a box form an arithmetic sequence. if the surface area of the box is 365.04 square units and the box's smallest dimension is 3 units, what is the volumes of the box in cubic
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the length width and height of a box form an arithmetic sequence. if the surface area of the box is 365.04 square units and the box's smallest dimension is 3 units, what is the volumes of the box in cubic units?

User Hanzla Habib
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8.2k points

1 Answer

7 votes

Answer:

the answer will be 365.04÷3

=121.68

User Abraxascarab
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