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What is the sum of the geometric sequence 1, 3, 9, ... if there are 14 terms? (5 points)

User AJStacy
by
8.7k points

1 Answer

5 votes

Answer:

287

Explanation:

the formulae is Sn=n\2(2a+(n-1)d)

where n=14,

d=3

and a=1

therefore,

Sn=14\2(2*1+(14-1)3)

Sn=7(2+(13)3)

Sn=7(2+39)

Sn=7(41)

Sn=287

User WayneC
by
8.3k points

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