Question

Sodium lamps give off light at

589 nm. When that light passes
through a diffraction grating with
d = 3.88 x 10-6 m, what is the angle of
its second order (m = 2) maximum?

Answer 1

Answer:17.67

Step-by-step explanation:

Answer 2

θ = 17.67°

Step-by-step explanation:

The grating equation can be used here to find the angle. The grating equation is given as follows:

`m\lambda = dSin\ \theta`

where,

m = order = 2

d = 3.88 x 10⁻⁶ m

λ = wavelength of light = 589 nm = 5.89 x 10⁻⁷ m

θ = angle = ?

Therefore, using these values in the equation, we get:

`(2)(5.89\ x\ 10^(-7)\ m) = (3.88\ x\ 10^(-6)\ m)Sin\theta \\Sin\theta = ((2)(5.89\ x\ 10^(-7)\ m))/((3.88\ x\ 10^(-6)\ m))\\\\\theta = Sin^(-1)(0.3036)`

θ = 17.67°