Answer:
2 50ml bottles
Explanation:
Reading through the question, we have:
For 80mL
![C_1 = \pounds 55](https://img.qammunity.org/2022/formulas/mathematics/high-school/iwqu5sh732oxqdq98o2ee4j76kqr14pp73.png)
For 2 50mL bottles.
The cost is calculated by the original cost + half the original cost.
i.e.
![C_2 = \pounds 45 + (1)/(2) * \pounds 45](https://img.qammunity.org/2022/formulas/mathematics/high-school/8jxrcb6wmrw5tg0u68sa85abs3x4w9ode5.png)
![C_2 = \pounds 45 + \pounds 22.5](https://img.qammunity.org/2022/formulas/mathematics/high-school/lkibpi6p5l9t3k11orb7mqz30z58rn596e.png)
![C_2 = \pounds 67.5](https://img.qammunity.org/2022/formulas/mathematics/high-school/45kjgc7cn9zbo779i2ivgxqjcy2g3o84vo.png)
Next, is to calculate the unit price of each.
For 80mL
![C_1 = \pounds 55](https://img.qammunity.org/2022/formulas/mathematics/high-school/iwqu5sh732oxqdq98o2ee4j76kqr14pp73.png)
![Unit\ price = 55/80](https://img.qammunity.org/2022/formulas/mathematics/high-school/40b3qtndh9ssrblwl3s705hng65kjyltly.png)
![Unit\ price = 0.6875](https://img.qammunity.org/2022/formulas/mathematics/high-school/299ryetnkz1mq89wsxb8o1efuhpwhk5545.png)
For 2 50mL bottles.
![C_2 = \pounds 67.5](https://img.qammunity.org/2022/formulas/mathematics/high-school/45kjgc7cn9zbo779i2ivgxqjcy2g3o84vo.png)
![Unit\ price - 67.5/(2 * 50)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ptzdi0nqv3vo8t7zcdppbtvo4k9phkwwfi.png)
![Unit\ price = 67.5/100](https://img.qammunity.org/2022/formulas/mathematics/high-school/w3lkqrkmuz9rtokwjr6em4fojn8hrwvnx7.png)
![Unit\ price = 0.675](https://img.qammunity.org/2022/formulas/mathematics/high-school/hlqduqe9xmnj5ajdxmmda6f3ts5a1rmaw0.png)
By comparison, the 2 50mL is the best buy because it has smaller unit price