Question

Given isosceles right triangle CDE with m∠D = 90, sin C = sin D

Answer 1

Answer:True

Explanation:

Given

`\angle D=90^(\circ)`

For isosceles triangle , CD=DE (x=y)

from figure,

`\sin C=(y)/(H)\\\\\sin D=(x)/(H)\\\\\text{CD=DE}\\\\\therefore \sin C=\sin D=(x)/(H)=(y)/(H)`

Thus, the given statement is true